![SOLVED: Prove that if [A, B] = 0 then there exists a complete set of eigenvectors that are simultaneous eigenvectors of both operators. Prove that the converse is also true: Namely, if SOLVED: Prove that if [A, B] = 0 then there exists a complete set of eigenvectors that are simultaneous eigenvectors of both operators. Prove that the converse is also true: Namely, if](https://cdn.numerade.com/ask_images/bd917aded35a4b45be5e4e64360fb86c.jpg)
SOLVED: Prove that if [A, B] = 0 then there exists a complete set of eigenvectors that are simultaneous eigenvectors of both operators. Prove that the converse is also true: Namely, if
An Exact Strong Converse Inequality for the Weighted Simultaneous Approximation by the Bernstein Operator
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